What is expand e^{2t}(-sin(2t)+1) ?

The solution to expand e^{2t}(-sin(2t)+1) is -e^{2t}sin(2t)+e^{2t}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand e^{2t}(-sin(2t)+1)

expand

e^{2 t} (- sin (2 t) + 1)

- e^{2 t} sin (2 t) + e^{2 t}

Solution steps

e^{2 t} (- sin (2 t) + 1)

Apply the distributive law:

a (b + c) = ab + a c

a = e^{2 t}, b = - sin (2 t), c = 1

= e^{2 t} (- sin (2 t)) + e^{2 t} \cdot 1

Apply minus-plus rules

+ (- a) = - a

= - e^{2 t} sin (2 t) + 1 \cdot e^{2 t}

Multiply:

1 \cdot e^{2 t} = e^{2 t}

= - e^{2 t} sin (2 t) + e^{2 t}

\frac{1}{( s ^{2} + 1 ) ^{3}}

lo g_{10} (x^{3} y z^{5})

x (5 - x)

0.03 \cdot 5 (1. 2^{5})

(x + ux + x - ux)^{2}

What is expand e^{2t}(-sin(2t)+1) ?
The solution to expand e^{2t}(-sin(2t)+1) is -e^{2t}sin(2t)+e^{2t}