What is (1+e^{iθ})^2 ?

The solution to (1+e^{iθ})^2 is (1+cos(θ)+isin(θ))^2

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simplify (1+e^{iθ})^2

simplify

(1 + e^{i θ})^{2}

(1 + cos (θ) + i sin (θ))^{2}

Solution steps

(1 + e^{i θ})^{2}

Apply imaginary number rule:

e^{ia} = cos (a) + i sin (a)

= (1 + cos (θ) + i sin (θ))^{2}

(3 x - 2) l e f t (x + 2)

A (6, 2) y B (5, - 4)

(- r cos (x) + v cos (y) + d)^{2}

\frac{4}{x ( x - 1 )}

4 (x - e^{x})