What is expand (2x^3-4x^2-12x+3)/((x-1)^2) ?

The solution to expand (2x^3-4x^2-12x+3)/((x-1)^2) is (2x^3-4x^2-12x+3)/(x^2-2x+1)

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expand (2x^3-4x^2-12x+3)/((x-1)^2)

expand

\frac{2 x ^{3} - 4 x ^{2} - 12 x + 3}{( x - 1 ) ^{2}}

\frac{2 x ^{3} - 4 x ^{2} - 12 x + 3}{x ^{2} - 2 x + 1}

Solution steps

\frac{2 x ^{3} - 4 x ^{2} - 12 x + 3}{( x - 1 ) ^{2}}

(x - 1)^{2} = x^{2} - 2 x + 1

= \frac{2 x ^{3} - 4 x ^{2} - 12 x + 3}{x ^{2} - 2 x + 1}

\frac{x + 11}{( x - 2 ) ( x + 7 )}

(- 2 + \frac{i - 1}{n})^{3}

(3 - x + 1)^{2}

lo g_{10} (3) (x - 1)

cos ((2 n + 1) π)

What is expand (2x^3-4x^2-12x+3)/((x-1)^2) ?
The solution to expand (2x^3-4x^2-12x+3)/((x-1)^2) is (2x^3-4x^2-12x+3)/(x^2-2x+1)