What is expand 4(3/(sqrt(13))x-2/(sqrt(13))y)^2 ?

The solution to expand 4(3/(sqrt(13))x-2/(sqrt(13))y)^2 is (4(9x^2-12xy+4y^2))/(13)

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expand 4(3/(sqrt(13))x-2/(sqrt(13))y)^2

expand

4 (\frac{3}{13} x - \frac{2}{13} y)^{2}

\frac{4 ( 9 x ^{2} - 12 x y + 4 y ^{2} )}{13}

Solution steps

4 (\frac{3}{13} x - \frac{2}{13} y)^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

(\frac{3}{13} x - \frac{2}{13} y)^{2} = (\frac{3}{13} x)^{2} - 2 \cdot \frac{3}{13} x \frac{2}{13} y + (\frac{2}{13} y)^{2}

= 4 ((\frac{3}{13} x)^{2} - 2 \cdot \frac{3}{13} x \frac{2}{13} y + (\frac{2}{13} y)^{2})

Simplify

(\frac{3}{13} x)^{2} - 2 \cdot \frac{3}{13} x \frac{2}{13} y + (\frac{2}{13} y)^{2} : \frac{9 x ^{2} - 12 x y + 4 y ^{2}}{13}

= 4 \cdot \frac{9 x ^{2} - 12 x y + 4 y ^{2}}{13}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{4 ( 9 x ^{2} - 12 x y + 4 y ^{2} )}{13}

(x + 2) e^{x}

(e^{t} + e^{t} t)^{2}

\frac{( b - a ) ^{2}}{12}

(a - bi)^{4}

(x + 8)^{2}

What is expand 4(3/(sqrt(13))x-2/(sqrt(13))y)^2 ?
The solution to expand 4(3/(sqrt(13))x-2/(sqrt(13))y)^2 is (4(9x^2-12xy+4y^2))/(13)