What is (-1-x)(-3/2-x)(-1/2-x) ?

The solution to (-1-x)(-3/2-x)(-1/2-x) is ((-1-x)(-2x-3)(-2x-1))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (-1-x)(-3/2-x)(-1/2-x)

simplify

(- 1 - x) (- \frac{3}{2} - x) (- \frac{1}{2} - x)

\frac{( - 1 - x ) ( - 2 x - 3 ) ( - 2 x - 1 )}{4}

Solution steps

(- 1 - x) (- \frac{3}{2} - x) (- \frac{1}{2} - x)

Simplify

- \frac{3}{2} - x : \frac{- 2 x - 3}{2}

= (- 1 - x) \frac{- 2 x - 3}{2} (- \frac{1}{2} - x)

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( - 1 - x ) ( - 2 x - 3 ) ( - \frac{1}{2} - x )}{2}

Simplify

(- 1 - x) (- 2 x - 3) (- \frac{1}{2} - x) : \frac{( - 1 - x ) ( - 2 x - 3 ) ( - x \cdot 2 - 1 )}{2}

= \frac{\frac{( - 1 - x ) ( - 2 x - 3 ) ( - x \cdot 2 - 1 )}{2}}{2}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( - 1 - x ) ( - 2 x - 3 ) ( - x \cdot 2 - 1 )}{2 \cdot 2}

Multiply the numbers:

2 \cdot 2 = 4

= \frac{( - 1 - x ) ( - 2 x - 3 ) ( - x \cdot 2 - 1 )}{4}

= \frac{( - 1 - x ) ( - 2 x - 3 ) ( - 2 x - 1 )}{4}

(\frac{x ^{2}}{2} + \frac{a}{x})^{6}

2 sin^{2} (2 t) + 2 (e^{t} - 2)^{2}

(x^{2} + y^{2}) \cdot x^{2} + y^{2}

lo g_{5} (x) (x + 2)

(cos (x)) (1 + cos (x))

What is (-1-x)(-3/2-x)(-1/2-x) ?
The solution to (-1-x)(-3/2-x)(-1/2-x) is ((-1-x)(-2x-3)(-2x-1))/4