What is expand 1/2 (-(ln(5x))/(2x^2)-1/(4x^2))+C ?

The solution to expand 1/2 (-(ln(5x))/(2x^2)-1/(4x^2))+C is -(ln(5x))/(4x^2)-1/(8x^2)+C

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expand 1/2 (-(ln(5x))/(2x^2)-1/(4x^2))+C

expand

\frac{1}{2} (- \frac{ln ( 5 x )}{2 x ^{2}} - \frac{1}{4 x ^{2}}) + C

- \frac{ln ( 5 x )}{4 x ^{2}} - \frac{1}{8 x ^{2}} + C

Solution steps

\frac{1}{2} (- \frac{ln ( 5 x )}{2 x ^{2}} - \frac{1}{4 x ^{2}}) + C

Expand

\frac{1}{2} (- \frac{ln ( 5 x )}{2 x ^{2}} - \frac{1}{4 x ^{2}}) : - \frac{ln ( 5 x )}{4 x ^{2}} - \frac{1}{8 x ^{2}}

= - \frac{ln ( 5 x )}{4 x ^{2}} - \frac{1}{8 x ^{2}} + C

t (x) x^{^{''}} - (t (x) + 3) x^{^{'}} + 3 x

(2 x + 3) x^{2} + 3 x

\frac{( n ( n + 1 ) ( 2 n + 1 ) )}{6}

\frac{2}{( 1 - x ) ^{2}}

\frac{1}{s ( s + 3 ) ^{2}}

What is expand 1/2 (-(ln(5x))/(2x^2)-1/(4x^2))+C ?
The solution to expand 1/2 (-(ln(5x))/(2x^2)-1/(4x^2))+C is -(ln(5x))/(4x^2)-1/(8x^2)+C