What is expand dx(x^2-3x+2)(2x^3+1) ?

The solution to expand dx(x^2-3x+2)(2x^3+1) is 2x^5dx-6x^4dx+4x^3dx+x^2dx-3xdx+2dx

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expand dx(x^2-3x+2)(2x^3+1)

expand

d x (x^{2} - 3 x + 2) (2 x^{3} + 1)

2 x^{5} d x - 6 x^{4} d x + 4 x^{3} d x + x^{2} d x - 3 x d x + 2 d x

Solution steps

d x (x^{2} - 3 x + 2) (2 x^{3} + 1)

Expand

(x^{2} - 3 x + 2) (2 x^{3} + 1) : 2 x^{5} - 6 x^{4} + 4 x^{3} + x^{2} - 3 x + 2

= d x (2 x^{5} - 6 x^{4} + 4 x^{3} + x^{2} - 3 x + 2)

Expand

d x (2 x^{5} - 6 x^{4} + 4 x^{3} + x^{2} - 3 x + 2) : 2 x^{5} d x - 6 x^{4} d x + 4 x^{3} d x + x^{2} d x - 3 x d x + 2 d x

= 2 x^{5} d x - 6 x^{4} d x + 4 x^{3} d x + x^{2} d x - 3 x d x + 2 d x

(3 + 2 i)^{4}

(3 + 2 i)^{3}

(x + 6) (x - 6)

\frac{1}{( 1 - i ) ^{5}}

(2 - sin (θ))^{2}

What is expand dx(x^2-3x+2)(2x^3+1) ?
The solution to expand dx(x^2-3x+2)(2x^3+1) is 2x^5dx-6x^4dx+4x^3dx+x^2dx-3xdx+2dx