What is expand (t-a)\H(t-a) ?

The solution to expand (t-a)\H(t-a) is t\H(t-a)-a\H(t-a)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (t-a)\H(t-a)

expand

(t - a) H (t - a)

t H (t - a) - a H (t - a)

Solution steps

(t - a) H (t - a)

= H (t - a) (t - a)

Apply the distributive law:

a (b - c) = ab - a c

a = H (t - a), b = t, c = a

= H (t - a) t - H (t - a) a

= t H (t - a) - a H (t - a)

(4 x^{3} + \frac{6}{x ^{3}}) (x^{\frac{3}{2}} - 4 x)

(x - 1) (2 x + 5)

\frac{x + 2}{( x + 1 ) ( x - 2 )}

(2 + \frac{t}{2})^{7}

(2 + 3) (3 - 2)

What is expand (t-a)\H(t-a) ?
The solution to expand (t-a)\H(t-a) is t\H(t-a)-a\H(t-a)