What is expand (2x(-x^2-3))/(25) ?

The solution to expand (2x(-x^2-3))/(25) is -(2x^3)/(25)-(6x)/(25)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (2x(-x^2-3))/(25)

expand

\frac{2 x ( - x ^{2} - 3 )}{25}

- \frac{2 x ^{3}}{25} - \frac{6 x}{25}

Solution steps

\frac{2 x ( - x ^{2} - 3 )}{25}

Expand

2 x (- x^{2} - 3) : - 2 x^{3} - 6 x

= \frac{- 2 x ^{3} - 6 x}{25}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{- 2 x ^{3} - 6 x}{25} = - \frac{2 x ^{3}}{25} - \frac{6 x}{25}

= - \frac{2 x ^{3}}{25} - \frac{6 x}{25}

\frac{d ^{2}}{d r d s} ((r (s)) (\frac{1}{r ( s )} + \frac{1}{s}))

(x^{3})^{2}

x^{s i n (π)} (cos (π) ln (π) + \frac{sin ( π )}{π})

sin (x) (sec (x) + cot (x))

\frac{- 2 x ^{3} - 1}{( x ^{3} - 1 ) ^{2}}

What is expand (2x(-x^2-3))/(25) ?
The solution to expand (2x(-x^2-3))/(25) is -(2x^3)/(25)-(6x)/(25)