What is (x+1/3)(x-1/3) ?

The solution to (x+1/3)(x-1/3) is ((3x+1)(3x-1))/9

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simplify (x+1/3)(x-1/3)

simplify

(x + \frac{1}{3}) (x - \frac{1}{3})

\frac{( 3 x + 1 ) ( 3 x - 1 )}{9}

Solution steps

(x + \frac{1}{3}) (x - \frac{1}{3})

Simplify

x + \frac{1}{3} : \frac{3 x + 1}{3}

= \frac{3 x + 1}{3} (x - \frac{1}{3})

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 3 x + 1 ) ( x - \frac{1}{3} )}{3}

Simplify

(3 x + 1) (x - \frac{1}{3}) : \frac{( 3 x + 1 ) ( x \cdot 3 - 1 )}{3}

= \frac{\frac{( 3 x + 1 ) ( x \cdot 3 - 1 )}{3}}{3}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( 3 x + 1 ) ( x \cdot 3 - 1 )}{3 \cdot 3}

Multiply the numbers:

3 \cdot 3 = 9

= \frac{( 3 x + 1 ) ( x \cdot 3 - 1 )}{9}

= \frac{( 3 x + 1 ) ( 3 x - 1 )}{9}

\frac{( 8 n ) !}{( 8 ( n + 1 ) ) !}

\frac{1}{9} (e^{3 x} \cdot 3 x - e^{3 x})

(- 2 + 2 i)^{5}

- \frac{1}{4} (6 e^{\frac{x}{2}} + e^{x})

(2 x^{2} + \frac{1}{x})^{9}