What is expand (k(3k-1))/2+(3k+1) ?

The solution to expand (k(3k-1))/2+(3k+1) is (3k^2)/2-k/2+3k+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (k(3k-1))/2+(3k+1)

expand

\frac{k ( 3 k - 1 )}{2} + (3 k + 1)

\frac{3 k ^{2}}{2} - \frac{k}{2} + 3 k + 1

Solution steps

\frac{k ( 3 k - 1 )}{2} + (3 k + 1)

Remove parentheses:

(a) = a

= \frac{k ( 3 k - 1 )}{2} + 3 k + 1

Expand

k (3 k - 1) : 3 k^{2} - k

= \frac{3 k ^{2} - k}{2} + 3 k + 1

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{3 k ^{2} - k}{2} = \frac{3 k ^{2}}{2} - \frac{k}{2}

= \frac{3 k ^{2}}{2} - \frac{k}{2} + 3 k + 1

\frac{( x - 1 ) ( x - 3 )}{( x + 1 )}

F (0, - 2)

(sin (x) + cos (2 x))^{2}

4 (\frac{3}{4} x + y = - 3)

\frac{34 - 17 s}{( 2 s - 1 ) ( s ^{2} - 2 s + 5 )}

What is expand (k(3k-1))/2+(3k+1) ?
The solution to expand (k(3k-1))/2+(3k+1) is (3k^2)/2-k/2+3k+1