What is expand ((4-y^2)^2)/2 ?

The solution to expand ((4-y^2)^2)/2 is (y^4)/2-4y^2+8

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expand ((4-y^2)^2)/2

expand

\frac{( 4 - y ^{2} ) ^{2}}{2}

\frac{y ^{4}}{2} - 4 y^{2} + 8

Solution steps

\frac{( 4 - y ^{2} ) ^{2}}{2}

(4 - y^{2})^{2} = 16 - 8 y^{2} + y^{4}

= \frac{16 - 8 y ^{2} + y ^{4}}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{16 - 8 y ^{2} + y ^{4}}{2} = \frac{16}{2} - \frac{8 y ^{2}}{2} + \frac{y ^{4}}{2}

= \frac{16}{2} - \frac{8 y ^{2}}{2} + \frac{y ^{4}}{2}

Divide the numbers:

\frac{16}{2} = 8

= 8 - \frac{8 y ^{2}}{2} + \frac{y ^{4}}{2}

Divide the numbers:

\frac{8}{2} = 4

= 8 - 4 y^{2} + \frac{y ^{4}}{2}

Rewrite in standard form

= \frac{y ^{4}}{2} - 4 y^{2} + 8

\frac{1}{s ( s - 2 )}

ln (z) (z - 1)^{4}

\frac{cos ( x )}{( 1 - sin ( x ) ) ^{2}}

\frac{x - 1}{2 x ( x + 1 )}

\frac{1 - e ^{- s}}{s ( s ^{2} + 2 s + 5 )}

What is expand ((4-y^2)^2)/2 ?
The solution to expand ((4-y^2)^2)/2 is (y^4)/2-4y^2+8