What is expand (16(x+1))/((x-2)^2(x^2+4)) ?

The solution to expand (16(x+1))/((x-2)^2(x^2+4)) is (16x+16)/(x^4+8x^2-4x^3-16x+16)

Popular >

expand (16(x+1))/((x-2)^2(x^2+4))

expand

\frac{16 ( x + 1 )}{( x - 2 ) ^{2} ( x ^{2} + 4 )}

\frac{16 x + 16}{x ^{4} + 8 x ^{2} - 4 x ^{3} - 16 x + 16}

Solution steps

\frac{16 ( x + 1 )}{( x - 2 ) ^{2} ( x ^{2} + 4 )}

(x - 2)^{2} = x^{2} - 4 x + 4

= \frac{16 ( x + 1 )}{( x ^{2} - 4 x + 4 ) ( x ^{2} + 4 )}

Expand

(x^{2} - 4 x + 4) (x^{2} + 4) : x^{4} + 8 x^{2} - 4 x^{3} - 16 x + 16

= \frac{16 ( x + 1 )}{x ^{4} + 8 x ^{2} - 4 x ^{3} - 16 x + 16}

Expand

16 (x + 1) : 16 x + 16

= \frac{16 x + 16}{x ^{4} + 8 x ^{2} - 4 x ^{3} - 16 x + 16}

\frac{5 ( 3 b ^{2} + 4 b - 6 )}{2}

(x^{4} + 3 x^{2} - 2)^{5}

\frac{sin ( 3 - x )}{( x - 3 ) \times ( x ^{2} + 1 )}

(x - y^{2}) d x + 2 x y d y

\frac{1}{( z - 1 ) ( z - 2 )}

What is expand (16(x+1))/((x-2)^2(x^2+4)) ?
The solution to expand (16(x+1))/((x-2)^2(x^2+4)) is (16x+16)/(x^4+8x^2-4x^3-16x+16)