What are the solutions to the equation 2x^2-28=0 ?

The solutions to the equation 2x^2-28=0 are x=sqrt(14),x=-sqrt(14)

Find the zeros of 2x^2-28=0

The zeros of 2x^2-28=0 are x=sqrt(14),x=-sqrt(14)

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2 x^{2} - 28 = 0

x = 14, x = - 14

Solution steps

2 x^{2} - 28 = 0

Move

28

to the right side

2 x^{2} = 28

Divide both sides by

2

x^{2} = 14

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 14, x = - 14

16 x - 4 + 5 x = - 67

\frac{3 ^{2 n} \cdot 2 5 ^{2 n - 1}}{1 5 ^{n - 1}}

(x - 1)^{2} = 2 x - 2

x^{2} + 4 x - 21 \leq 0

\frac{3 x}{25} = \frac{9}{50}

What are the solutions to the equation 2x^2-28=0 ?
The solutions to the equation 2x^2-28=0 are x=sqrt(14),x=-sqrt(14)
Find the zeros of 2x^2-28=0
The zeros of 2x^2-28=0 are x=sqrt(14),x=-sqrt(14)