What is expand (e^{-2s})/(s(s+3)(2s+1)(s+1)) ?

The solution to expand (e^{-2s})/(s(s+3)(2s+1)(s+1)) is (e^{-2s})/(2s^4+9s^3+10s^2+3s)

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expand (e^{-2s})/(s(s+3)(2s+1)(s+1))

expand

\frac{e ^{- 2 s}}{s ( s + 3 ) ( 2 s + 1 ) ( s + 1 )}

\frac{e ^{- 2 s}}{2 s ^{4} + 9 s ^{3} + 10 s ^{2} + 3 s}

Solution steps

\frac{e ^{- 2 s}}{s ( s + 3 ) ( 2 s + 1 ) ( s + 1 )}

Expand

s (s + 3) (2 s + 1) (s + 1) : 2 s^{4} + 9 s^{3} + 10 s^{2} + 3 s

= \frac{e ^{- 2 s}}{2 s ^{4} + 9 s ^{3} + 10 s ^{2} + 3 s}

\frac{( 2 x ^{2} + 1 ) ^{2}}{( x - 1 ) ^{2} ( x ^{2} + x )}

\frac{s}{( s + 2 ) ^{2}}

I n (x 1 + x^{2})

A (- 3, - 1) y B (5, 2)

\frac{3 ^{n}}{( a + 3 ^{n + 1} ) ( a + 3 ^{n} )}

What is expand (e^{-2s})/(s(s+3)(2s+1)(s+1)) ?
The solution to expand (e^{-2s})/(s(s+3)(2s+1)(s+1)) is (e^{-2s})/(2s^4+9s^3+10s^2+3s)