What is expand 6/((s-3)(s^2-4s)) ?

The solution to expand 6/((s-3)(s^2-4s)) is 6/(s^3-7s^2+12s)

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expand 6/((s-3)(s^2-4s))

expand

\frac{6}{( s - 3 ) ( s ^{2} - 4 s )}

\frac{6}{s ^{3} - 7 s ^{2} + 12 s}

Solution steps

\frac{6}{( s - 3 ) ( s ^{2} - 4 s )}

Expand

(s - 3) (s^{2} - 4 s) : s^{3} - 7 s^{2} + 12 s

= \frac{6}{s ^{3} - 7 s ^{2} + 12 s}

2 (5 + 3)

2 (- \frac{5 π}{12}) + \frac{π}{2}

(1 + sin (x)) (sin (x))

(r sin (θ) - r^{2} + 4) (r)

\frac{x ^{3} ( x - 1 ) ^{2}}{( 2 x + 1 ) ^{2}}

What is expand 6/((s-3)(s^2-4s)) ?
The solution to expand 6/((s-3)(s^2-4s)) is 6/(s^3-7s^2+12s)