What is (x-1/(x^2))*(x+1/(x^2)) ?

The solution to (x-1/(x^2))*(x+1/(x^2)) is ((x^3-1)(x^3+1))/(x^4)

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simplify (x-1/(x^2))*(x+1/(x^2))

simplify

(x - \frac{1}{x ^{2}}) \cdot (x + \frac{1}{x ^{2}})

\frac{( x ^{3} - 1 ) ( x ^{3} + 1 )}{x ^{4}}

Solution steps

(x - \frac{1}{x ^{2}}) (x + \frac{1}{x ^{2}})

Join

x - \frac{1}{x ^{2}} : \frac{x ^{3} - 1}{x ^{2}}

= \frac{x ^{3} - 1}{x ^{2}} (x + \frac{1}{x ^{2}})

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( x ^{3} - 1 ) ( x + \frac{1}{x ^{2}} )}{x ^{2}}

Simplify

(x^{3} - 1) (x + \frac{1}{x ^{2}}) : \frac{( x ^{3} - 1 ) ( x ^{3} + 1 )}{x ^{2}}

= \frac{\frac{( x ^{3} - 1 ) ( x ^{3} + 1 )}{x ^{2}}}{x ^{2}}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( x ^{3} - 1 ) ( x ^{3} + 1 )}{x ^{2} x ^{2}}

Simplify

x^{2} x^{2} : x^{4}

= \frac{( x ^{3} - 1 ) ( x ^{3} + 1 )}{x ^{4}}

cos (2 x^{3} - 9 x) (6 x^{2} - 9)

- 2 (2 + 3) 2 - 3

\frac{4}{( x - 1 ) ( x + 3 )}

(x + y) \cdot (x - y)

(x + \frac{1}{5}) (x + \frac{2}{5})

What is (x-1/(x^2))*(x+1/(x^2)) ?
The solution to (x-1/(x^2))*(x+1/(x^2)) is ((x^3-1)(x^3+1))/(x^4)