What is expand (2x^3-4x^2-15x+6)/((x-1)^2) ?

The solution to expand (2x^3-4x^2-15x+6)/((x-1)^2) is (2x^3-4x^2-15x+6)/(x^2-2x+1)

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expand (2x^3-4x^2-15x+6)/((x-1)^2)

expand

\frac{2 x ^{3} - 4 x ^{2} - 15 x + 6}{( x - 1 ) ^{2}}

\frac{2 x ^{3} - 4 x ^{2} - 15 x + 6}{x ^{2} - 2 x + 1}

Solution steps

\frac{2 x ^{3} - 4 x ^{2} - 15 x + 6}{( x - 1 ) ^{2}}

(x - 1)^{2} = x^{2} - 2 x + 1

= \frac{2 x ^{3} - 4 x ^{2} - 15 x + 6}{x ^{2} - 2 x + 1}

(\frac{1}{2} x - 3)^{4}

\frac{x - 1}{( x + 1 ) ^{2}}

\frac{( 1 + i ) ^{19}}{( 1 - i ) ^{17}}

(3 x - y = 4,) (x + y = 3)

\frac{( x + 2 ) ^{2}}{2}

What is expand (2x^3-4x^2-15x+6)/((x-1)^2) ?
The solution to expand (2x^3-4x^2-15x+6)/((x-1)^2) is (2x^3-4x^2-15x+6)/(x^2-2x+1)