What is expand (3n^2(n+1))/(2n^3-1) ?

The solution to expand (3n^2(n+1))/(2n^3-1) is (3n^3+3n^2)/(2n^3-1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (3n^2(n+1))/(2n^3-1)

expand

\frac{3 n ^{2} ( n + 1 )}{2 n ^{3} - 1}

\frac{3 n ^{3} + 3 n ^{2}}{2 n ^{3} - 1}

Solution steps

\frac{3 n ^{2} ( n + 1 )}{2 n ^{3} - 1}

Expand

3 n^{2} (n + 1) : 3 n^{3} + 3 n^{2}

= \frac{3 n ^{3} + 3 n ^{2}}{2 n ^{3} - 1}

(4 - \frac{3}{x + 2}) (1 + \frac{5}{x - 1})

\frac{2 x ^{3}}{( x - 1 ) ( x ^{2} + 3 )}

cos ((n + 1) π)

(x + \frac{1}{9}) (x - \frac{1}{3})

(23 + j^{2})^{4}

What is expand (3n^2(n+1))/(2n^3-1) ?
The solution to expand (3n^2(n+1))/(2n^3-1) is (3n^3+3n^2)/(2n^3-1)