What is expand (4-4sin(θ))^2 ?

The solution to expand (4-4sin(θ))^2 is 16-32sin(θ)+16sin^2(θ)

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expand (4-4sin(θ))^2

expand

(4 - 4 sin (θ))^{2}

16 - 32 sin (θ) + 16 sin^{2} (θ)

Solution steps

(4 - 4 sin (θ))^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

(4 - 4 sin (θ))^{2} = 4^{2} - 2 \cdot 4 \cdot 4 sin (θ) + (4 sin (θ))^{2}

= 4^{2} - 2 \cdot 4 \cdot 4 sin (θ) + (4 sin (θ))^{2}

Simplify

4^{2} - 2 \cdot 4 \cdot 4 sin (θ) + (4 sin (θ))^{2} : 16 - 32 sin (θ) + 16 sin^{2} (θ)

= 16 - 32 sin (θ) + 16 sin^{2} (θ)

(1 - x) x

(1 + x 6)^{2}

(\frac{1}{2} - \frac{x}{3}) x^{2} e^{2 x}

6.9 (e^{- 0.24 t} - 0.24 e^{- 0.24 t} t)

2 (2 csc (2 x) + x (- csc^{2} (x) + sec^{2} (x)))

What is expand (4-4sin(θ))^2 ?
The solution to expand (4-4sin(θ))^2 is 16-32sin(θ)+16sin^2(θ)