What is (1/5-x)(2/5-x) ?

The solution to (1/5-x)(2/5-x) is ((-5x+1)(-5x+2))/(25)

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simplify (1/5-x)(2/5-x)

simplify

(\frac{1}{5} - x) (\frac{2}{5} - x)

\frac{( - 5 x + 1 ) ( - 5 x + 2 )}{25}

Solution steps

(\frac{1}{5} - x) (\frac{2}{5} - x)

Simplify

\frac{1}{5} - x : \frac{- 5 x + 1}{5}

= \frac{- 5 x + 1}{5} (\frac{2}{5} - x)

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( - 5 x + 1 ) ( \frac{2}{5} - x )}{5}

Simplify

(- 5 x + 1) (\frac{2}{5} - x) : \frac{( - 5 x + 1 ) ( - x \cdot 5 + 2 )}{5}

= \frac{\frac{( - 5 x + 1 ) ( - x \cdot 5 + 2 )}{5}}{5}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( - 5 x + 1 ) ( - x \cdot 5 + 2 )}{5 \cdot 5}

Multiply the numbers:

5 \cdot 5 = 25

= \frac{( - 5 x + 1 ) ( - x \cdot 5 + 2 )}{25}

= \frac{( - 5 x + 1 ) ( - 5 x + 2 )}{25}

(2 x + 5) (x + 5) (x - 5)

(x + 1 + 12 - x)^{2}

(- 3 + \frac{3}{x ^{5}}) (x^{4} + 5)

9 - x (x^{4} + x^{3} + x^{2} + x + 1)

- \frac{( x + r - 1 ) ( x + r + 2 )}{( x + r ) ( - x + r + 4 )}

What is (1/5-x)(2/5-x) ?
The solution to (1/5-x)(2/5-x) is ((-5x+1)(-5x+2))/(25)