What is expand log_{10}(5)(2x(8x+7)) ?

The solution to expand log_{10}(5)(2x(8x+7)) is 16log_{10}(5)x^2+14log_{10}(5)x

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expand log_{10}(5)(2x(8x+7))

expand

lo g_{10} (5) (2 x (8 x + 7))

16 lo g_{10} (5) x^{2} + 14 lo g_{10} (5) x

Solution steps

lo g_{10} (5) (2 x (8 x + 7))

Remove parentheses:

(a) = a

= lo g_{10} (5) \cdot 2 x (8 x + 7)

= 2 lo g_{10} (5) x (8 x + 7)

Apply the distributive law:

a (b + c) = ab + a c

a = lo g_{10} (5) \cdot 2 x, b = 8 x, c = 7

= lo g_{10} (5) \cdot 2 x \cdot 8 x + lo g_{10} (5) \cdot 2 x \cdot 7

= 2 \cdot 8 lo g_{10} (5) xx + 2 \cdot 7 lo g_{10} (5) x

Simplify

2 \cdot 8 lo g_{10} (5) xx + 2 \cdot 7 lo g_{10} (5) x : 16 lo g_{10} (5) x^{2} + 14 lo g_{10} (5) x

= 16 lo g_{10} (5) x^{2} + 14 lo g_{10} (5) x

\frac{\partial}{\partial x} ((z) (2 x yz - e^{z}))

\frac{4 x + 24}{( x - 2 ) ( x + 3 )}

\frac{x}{( x + 1 ) ( x + 4 )}

(2 sin (x) - 1)^{2}

- \frac{s ( - 2 s ^{2} - 5 )}{( s + 1 ) ( s - 1 ) ( s ^{2} + 1 )}

What is expand log_{10}(5)(2x(8x+7)) ?
The solution to expand log_{10}(5)(2x(8x+7)) is 16log_{10}(5)x^2+14log_{10}(5)x