What is (y^2+5/2)(y^2-3/2) ?

The solution to (y^2+5/2)(y^2-3/2) is ((2y^2+5)(2y^2-3))/4

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simplify (y^2+5/2)(y^2-3/2)

simplify

(y^{2} + \frac{5}{2}) (y^{2} - \frac{3}{2})

\frac{( 2 y ^{2} + 5 ) ( 2 y ^{2} - 3 )}{4}

Solution steps

(y^{2} + \frac{5}{2}) (y^{2} - \frac{3}{2})

Simplify

y^{2} + \frac{5}{2} : \frac{2 y ^{2} + 5}{2}

= \frac{2 y ^{2} + 5}{2} (y^{2} - \frac{3}{2})

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 2 y ^{2} + 5 ) ( y ^{2} - \frac{3}{2} )}{2}

Simplify

(2 y^{2} + 5) (y^{2} - \frac{3}{2}) : \frac{( 2 y ^{2} + 5 ) ( y ^{2} \cdot 2 - 3 )}{2}

= \frac{\frac{( 2 y ^{2} + 5 ) ( y ^{2} \cdot 2 - 3 )}{2}}{2}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( 2 y ^{2} + 5 ) ( y ^{2} \cdot 2 - 3 )}{2 \cdot 2}

Multiply the numbers:

2 \cdot 2 = 4

= \frac{( 2 y ^{2} + 5 ) ( y ^{2} \cdot 2 - 3 )}{4}

= \frac{( 2 y ^{2} + 5 ) ( 2 y ^{2} - 3 )}{4}

(- \frac{x ^{3}}{4} + 2 y) \cdot (3 x^{2} - x y + y^{4})

(2 - \frac{1}{3} x)^{3}

x y^{3} d x + (y + 1) e^{- x} d y

\frac{( s + 3 )}{( s + 2 ) ( s + 4 ) ( s + 5 )}

\frac{5}{( s + 2 ) ( s ^{2} + 25 )}

What is (y^2+5/2)(y^2-3/2) ?
The solution to (y^2+5/2)(y^2-3/2) is ((2y^2+5)(2y^2-3))/4