What are the solutions to the equation 9(2x)^2-2=0 ?

The solutions to the equation 9(2x)^2-2=0 are x= 1/(3sqrt(2)),x=-1/(3sqrt(2))

Find the zeros of 9(2x)^2-2=0

The zeros of 9(2x)^2-2=0 are x= 1/(3sqrt(2)),x=-1/(3sqrt(2))

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9 (2 x)^{2} - 2 = 0

x = \frac{1}{3 2}, x = - \frac{1}{3 2}

Decimal Notation

x = 0.23570 \dots, x = - 0.23570 \dots

Solution steps

9 (2 x)^{2} - 2 = 0

Expand

9 (2 x)^{2} - 2 : 36 x^{2} - 2

36 x^{2} - 2 = 0

Move

2

to the right side

36 x^{2} = 2

Divide both sides by

36

x^{2} = \frac{1}{18}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{1}{18}, x = - \frac{1}{18}

\frac{1}{18} = \frac{1}{3 2}

- \frac{1}{18} = - \frac{1}{3 2}

x = \frac{1}{3 2}, x = - \frac{1}{3 2}

- 7 (- a^{2}) (- b^{3})

(42)^{2}

\frac{x - 1}{x - 5} \geq \frac{x + 5}{x + 9}

\frac{1}{\frac{4}{2}}

5 < \frac{x - 6}{2} < 16

What are the solutions to the equation 9(2x)^2-2=0 ?
The solutions to the equation 9(2x)^2-2=0 are x= 1/(3sqrt(2)),x=-1/(3sqrt(2))
Find the zeros of 9(2x)^2-2=0
The zeros of 9(2x)^2-2=0 are x= 1/(3sqrt(2)),x=-1/(3sqrt(2))