What is expand e^x(e^x+e^{-x}) ?

The solution to expand e^x(e^x+e^{-x}) is e^{2x}+1

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expand e^x(e^x+e^{-x})

expand

e^{x} (e^{x} + e^{- x})

e^{2 x} + 1

Solution steps

e^{x} (e^{x} + e^{- x})

Apply the distributive law:

a (b + c) = ab + a c

a = e^{x}, b = e^{x}, c = e^{- x}

= e^{x} e^{x} + e^{x} e^{- x}

Simplify

e^{x} e^{x} + e^{x} e^{- x} : e^{2 x} + 1

= e^{2 x} + 1

(9 sin (x) - 9) (2 cos (x) + 3)

\frac{1 + x}{( 1 - x ) ^{3}}

a (b - c \mp d)

3 x^{2} + 6 x y^{2} + (6 x^{2} y + 4 y^{2}) y^{'} (x)

7 (\frac{1}{9} a + 2)

What is expand e^x(e^x+e^{-x}) ?
The solution to expand e^x(e^x+e^{-x}) is e^{2x}+1