What is expand ((4x+1)(3x-1))/(6x^2) ?

The solution to expand ((4x+1)(3x-1))/(6x^2) is 2-1/(6x)-1/(6x^2)

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expand ((4x+1)(3x-1))/(6x^2)

expand

\frac{( 4 x + 1 ) ( 3 x - 1 )}{6 x ^{2}}

2 - \frac{1}{6 x} - \frac{1}{6 x ^{2}}

Solution steps

\frac{( 4 x + 1 ) ( 3 x - 1 )}{6 x ^{2}}

Expand

(4 x + 1) (3 x - 1) : 12 x^{2} - x - 1

= \frac{12 x ^{2} - x - 1}{6 x ^{2}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{12 x ^{2} - x - 1}{6 x ^{2}} = \frac{12 x ^{2}}{6 x ^{2}} - \frac{x}{6 x ^{2}} - \frac{1}{6 x ^{2}}

= \frac{12 x ^{2}}{6 x ^{2}} - \frac{x}{6 x ^{2}} - \frac{1}{6 x ^{2}}

Cancel

\frac{12 x ^{2}}{6 x ^{2}} : 2

= 2 - \frac{x}{6 x ^{2}} - \frac{1}{6 x ^{2}}

Cancel

\frac{x}{6 x ^{2}} : \frac{1}{6 x}

= 2 - \frac{1}{6 x} - \frac{1}{6 x ^{2}}

lo g_{10} (3) (x - 6)

(L^{3} \cdot cos (q) - sin (q))^{2}

\frac{1}{s ( s - 1 ) ^{2}}

(1 - sec (x)) (sec^{2} (x))

2 (x + i y)^{2}

What is expand ((4x+1)(3x-1))/(6x^2) ?
The solution to expand ((4x+1)(3x-1))/(6x^2) is 2-1/(6x)-1/(6x^2)