What is y(1-1/((x^2+y^2))) ?

The solution to y(1-1/((x^2+y^2))) is (y(x^2+y^2-1))/(x^2+y^2)

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simplify y(1-1/((x^2+y^2)))

simplify

y (1 - \frac{1}{( x ^{2} + y ^{2} )})

\frac{y ( x ^{2} + y ^{2} - 1 )}{x ^{2} + y ^{2}}

Solution steps

y (1 - \frac{1}{x ^{2} + y ^{2}})

Join

1 - \frac{1}{x ^{2} + y ^{2}} : \frac{x ^{2} + y ^{2} - 1}{x ^{2} + y ^{2}}

= y \frac{x ^{2} + y ^{2} - 1}{x ^{2} + y ^{2}}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{y ( x ^{2} + y ^{2} - 1 )}{x ^{2} + y ^{2}}

\frac{( x + 3 ) ( 2 x - 1 )}{( 2 x + 1 ) ^{2}}

(x - \frac{2}{x ^{2}})^{9}

6 (11 + 7)

(6 + 2 i)^{2}

(4 - \frac{x}{16})^{6} (x - \frac{1}{x})^{2}

What is y(1-1/((x^2+y^2))) ?
The solution to y(1-1/((x^2+y^2))) is (y(x^2+y^2-1))/(x^2+y^2)