What is expand-2(4e^{-x^2}x^3-6e^{-x^2}x) ?

The solution to expand-2(4e^{-x^2}x^3-6e^{-x^2}x) is -8e^{-x^2}x^3+12e^{-x^2}x

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expand-2(4e^{-x^2}x^3-6e^{-x^2}x)

expand

- 2 (4 e^{- x^{2}} x^{3} - 6 e^{- x^{2}} x)

- 8 e^{- x^{2}} x^{3} + 12 e^{- x^{2}} x

Solution steps

- 2 (4 e^{- x^{2}} x^{3} - 6 e^{- x^{2}} x)

Apply the distributive law:

a (b - c) = ab - a c

a = - 2, b = 4 e^{- x^{2}} x^{3}, c = 6 e^{- x^{2}} x

= - 2 \cdot 4 e^{- x^{2}} x^{3} - (- 2) \cdot 6 e^{- x^{2}} x

Apply minus-plus rules

- (- a) = a

= - 2 \cdot 4 e^{- x^{2}} x^{3} + 2 \cdot 6 e^{- x^{2}} x

Simplify

- 2 \cdot 4 e^{- x^{2}} x^{3} + 2 \cdot 6 e^{- x^{2}} x : - 8 e^{- x^{2}} x^{3} + 12 e^{- x^{2}} x

= - 8 e^{- x^{2}} x^{3} + 12 e^{- x^{2}} x

\frac{x + 1}{2 ( x - 1 ) ( 4 x + 1 )}

(x + 5) l e f t (x - 5)

(r + sin (θ) - cos (θ)) d r

\frac{( s ^{3} + 2 )}{s ^{2} \cdot ( s ^{2} + 4 )}

(x^{3} + x y^{2} - y) d x + (y^{3} + x^{2} y - x) d y

What is expand-2(4e^{-x^2}x^3-6e^{-x^2}x) ?
The solution to expand-2(4e^{-x^2}x^3-6e^{-x^2}x) is -8e^{-x^2}x^3+12e^{-x^2}x