What is (1/x-x)(1/x+x) ?

The solution to (1/x-x)(1/x+x) is ((-x^2+1)(x^2+1))/(x^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (1/x-x)(1/x+x)

simplify

(\frac{1}{x} - x) (\frac{1}{x} + x)

\frac{( - x ^{2} + 1 ) ( x ^{2} + 1 )}{x ^{2}}

Solution steps

(\frac{1}{x} - x) (\frac{1}{x} + x)

Join

\frac{1}{x} - x : \frac{- x ^{2} + 1}{x}

= \frac{- x ^{2} + 1}{x} (\frac{1}{x} + x)

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( - x ^{2} + 1 ) ( \frac{1}{x} + x )}{x}

Simplify

(- x^{2} + 1) (\frac{1}{x} + x) : \frac{( - x ^{2} + 1 ) ( x ^{2} + 1 )}{x}

= \frac{\frac{( - x ^{2} + 1 ) ( x ^{2} + 1 )}{x}}{x}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( - x ^{2} + 1 ) ( x ^{2} + 1 )}{xx}

Apply exponent rule:

aa = a^{2}

xx = x^{2}

= \frac{( - x ^{2} + 1 ) ( x ^{2} + 1 )}{x ^{2}}

(3 + 4 i)^{12}

A (- 1, 1) y B (1, - 1)

(- 2 + 2 i 3)^{5}

(x + 3) (x - 3)

(a^{2 x} - a)^{3}

What is (1/x-x)(1/x+x) ?
The solution to (1/x-x)(1/x+x) is ((-x^2+1)(x^2+1))/(x^2)