What is expand ((2-x)^2)/4 ?

The solution to expand ((2-x)^2)/4 is (x^2)/4-x+1

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expand ((2-x)^2)/4

expand

\frac{( 2 - x ) ^{2}}{4}

\frac{x ^{2}}{4} - x + 1

Solution steps

\frac{( 2 - x ) ^{2}}{4}

(2 - x)^{2} = 4 - 4 x + x^{2}

= \frac{4 - 4 x + x ^{2}}{4}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{4 - 4 x + x ^{2}}{4} = \frac{4}{4} - \frac{4 x}{4} + \frac{x ^{2}}{4}

= \frac{4}{4} - \frac{4 x}{4} + \frac{x ^{2}}{4}

Apply rule

\frac{a}{a} = 1

\frac{4}{4} = 1

= 1 - \frac{4 x}{4} + \frac{x ^{2}}{4}

Divide the numbers:

\frac{4}{4} = 1

= 1 - x + \frac{x ^{2}}{4}

Rewrite in standard form

= \frac{x ^{2}}{4} - x + 1

(3 + 4 x^{3}) (2 x^{2} - \frac{1}{2 x})^{12}

(3 x - \frac{3}{4}) (3 x + \frac{3}{4})

(x + 2) (x - 1) (x - 7) (x + 7)

\frac{2 x ^{\frac{5}{3}} ( 4 t ^{2} - x )}{t ^{\frac{1}{3}}}

\frac{2 ( x + 1 )}{( 3 x + 7 ) ^{\frac{1}{3}}}