What is expand 4/(1+e^{-3(t-2))} ?

The solution to expand 4/(1+e^{-3(t-2))} is 4/(1+e^{-3t+6)}

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expand 4/(1+e^{-3(t-2))}

expand

\frac{4}{1 + e ^{- 3 (t - 2)}}

\frac{4}{1 + e ^{- 3 t + 6}}

Solution steps

\frac{4}{1 + e ^{- 3 (t - 2)}}

Expand

- 3 (t - 2) : - 3 t + 6

= \frac{4}{1 + e ^{- 3 t + 6}}

lo g_{10} (10000 z)

ln (2 x + 4) (3 x - 1)

\frac{( 3 x - 5 ) ( 4 x + 1 )}{( 2 x + 3 ) ( 5 x - 2 )}

(4 - 4 i)^{5}

(x^{2} + 1 + x^{2} - 1)^{2}

What is expand 4/(1+e^{-3(t-2))} ?
The solution to expand 4/(1+e^{-3(t-2))} is 4/(1+e^{-3t+6)}