What is expand (x-3-4i)(x-3+4i)(x)(x+1) ?

The solution to expand (x-3-4i)(x-3+4i)(x)(x+1) is x^4-5x^3+19x^2+25x

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expand (x-3-4i)(x-3+4i)(x)(x+1)

expand

(x - 3 - 4 i) (x - 3 + 4 i) (x) (x + 1)

x^{4} - 5 x^{3} + 19 x^{2} + 25 x

Solution steps

(x - 3 - 4 i) (x - 3 + 4 i) (x) (x + 1)

Apply rule:

(a) = a

(x) = x

= (x - 3 - 4 i) (x - 3 + 4 i) x (x + 1)

= x (x - 3 - 4 i) (x - 3 + 4 i) (x + 1)

Expand

x (x + 1) : x^{2} + x

= (x^{2} + x) (x - 3 - 4 i) (x - 3 + 4 i)

Expand

(x^{2} + x) (x - 3 - 4 i) : x^{3} - 2 x^{2} - 4 x^{2} i - 3 x - 4 x i

= (x^{3} - 2 x^{2} - 4 x^{2} i - 3 x - 4 x i) (x - 3 + 4 i)

Distribute parentheses

= x^{3} x + x^{3} (- 3) + x^{3} \cdot 4 i - 2 x^{2} x - 2 x^{2} (- 3) - 2 x^{2} \cdot 4 i - 4 x^{2} i x - 4 x^{2} i (- 3) - 4 x^{2} i 4 i - 3 xx - 3 x (- 3) - 3 x \cdot 4 i - 4 x i x - 4 x i (- 3) - 4 x i 4 i

Simplify

x^{3} x + x^{3} (- 3) + x^{3} \cdot 4 i - 2 x^{2} x - 2 x^{2} (- 3) - 2 x^{2} \cdot 4 i - 4 x^{2} i x - 4 x^{2} i (- 3) - 4 x^{2} i 4 i - 3 xx - 3 x (- 3) - 3 x \cdot 4 i - 4 x i x - 4 x i (- 3) - 4 x i 4 i : x^{4} - 5 x^{3} + 19 x^{2} + 25 x

= x^{4} - 5 x^{3} + 19 x^{2} + 25 x

\frac{x ^{2} - 4 x}{( x + 1 ) ^{2}}

\frac{d}{d t} ((w) (cos (t) sin (t) + t))

n^{2} (1 - cos (\frac{1}{n}))

\frac{X + 2}{( X + 1 ) ^{2}}

\frac{4 s + 5}{( s - 1 ) ^{2} ( s + 2 )}

What is expand (x-3-4i)(x-3+4i)(x)(x+1) ?
The solution to expand (x-3-4i)(x-3+4i)(x)(x+1) is x^4-5x^3+19x^2+25x