What is expand (e^t-e^{-t})(-e^{-t}) ?

The solution to expand (e^t-e^{-t})(-e^{-t}) is -1+e^{-2t}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (e^t-e^{-t})(-e^{-t})

expand

(e^{t} - e^{- t}) (- e^{- t})

- 1 + e^{- 2 t}

Solution steps

(e^{t} - e^{- t}) (- e^{- t})

Apply the distributive law:

a (b - c) = ab - a c

a = (- e^{- t}), b = e^{t}, c = e^{- t}

= (- e^{- t}) e^{t} - (- e^{- t}) e^{- t}

= e^{t} (- e^{- t}) - e^{- t} (- e^{- t})

Simplify

e^{t} (- e^{- t}) - e^{- t} (- e^{- t}) : - 1 + e^{- 2 t}

= - 1 + e^{- 2 t}

9 (\frac{2}{3} + 2 x)

A (5, - 2) y B (- 3, 1)

2 (cos (x) + sin (x))

\frac{10 ( 2 s + 3 )}{s ( s ^{2} + 2 s + 5 )}

\frac{( 2 x - 7 ) ^{2}}{4}

What is expand (e^t-e^{-t})(-e^{-t}) ?
The solution to expand (e^t-e^{-t})(-e^{-t}) is -1+e^{-2t}