What are the solutions to the equation (x+7)^2=2 ?

The solutions to the equation (x+7)^2=2 are x=sqrt(2)-7,x=-sqrt(2)-7

Find the zeros of (x+7)^2=2

The zeros of (x+7)^2=2 are x=sqrt(2)-7,x=-sqrt(2)-7

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(x + 7)^{2} = 2

x = 2 - 7, x = - 2 - 7

Decimal Notation

x = - 5.58578 \dots, x = - 8.41421 \dots

Solution steps

(x + 7)^{2} = 2

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 7 = 2 : x = 2 - 7

Solve

x + 7 = - 2 : x = - 2 - 7

The solutions to the quadratic equation are:

x = 2 - 7, x = - 2 - 7

x^{2} + y^{2} - 2 x y

t^{2} - 2 t - 3 = 0

2 (x + 3) = 12

x^{2} + 16 > 10 x

(x - 6) (x + 1)^{2} < 0

What are the solutions to the equation (x+7)^2=2 ?
The solutions to the equation (x+7)^2=2 are x=sqrt(2)-7,x=-sqrt(2)-7
Find the zeros of (x+7)^2=2
The zeros of (x+7)^2=2 are x=sqrt(2)-7,x=-sqrt(2)-7