What is expand-1/8 (e^{2x}-e^{-2x}) ?

The solution to expand-1/8 (e^{2x}-e^{-2x}) is -1/8 e^{2x}+1/8 e^{-2x}

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expand-1/8 (e^{2x}-e^{-2x})

expand

- \frac{1}{8} (e^{2 x} - e^{- 2 x})

- \frac{1}{8} e^{2 x} + \frac{1}{8} e^{- 2 x}

Solution steps

- \frac{1}{8} (e^{2 x} - e^{- 2 x})

Apply the distributive law:

a (b - c) = ab - a c

a = - \frac{1}{8}, b = e^{2 x}, c = e^{- 2 x}

= - \frac{1}{8} e^{2 x} - (- \frac{1}{8}) e^{- 2 x}

Apply minus-plus rules

- (- a) = a

= - \frac{1}{8} e^{2 x} + \frac{1}{8} e^{- 2 x}

(7 u, 7 v, 1 - u^{2} - v^{2}) \cdot (2 u, 2 v, 1)

4 (2 - 3)

- \frac{1}{( 1 - x ) ^{2}}

\frac{x - 20}{( x - 4 ) ( x + 1 )}

(x + 3 + 3)^{2}

What is expand-1/8 (e^{2x}-e^{-2x}) ?
The solution to expand-1/8 (e^{2x}-e^{-2x}) is -1/8 e^{2x}+1/8 e^{-2x}