What is ((1+sqrt(3))^4)/(16)-1-sqrt(3) ?

The solution to ((1+sqrt(3))^4)/(16)-1-sqrt(3) is 3/4

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simplify ((1+sqrt(3))^4)/(16)-1-sqrt(3)

simplify

\frac{( 1 + 3 ) ^{4}}{16} - 1 - 3

\frac{3}{4}

Decimal Notation

0.75

Solution steps

\frac{( 1 + 3 ) ^{4}}{16} - 1 - 3

Convert

- 1

to fraction

: \frac{- 16}{16}

= \frac{( 1 + 3 ) ^{4}}{16} + \frac{- 16}{16} - 3

Apply the fraction rule:

a = \frac{ab}{b}

= \frac{( 1 + 3 ) ^{4}}{16} + \frac{- 16}{16} + \frac{- 3 \cdot 16}{16}

\frac{( 1 + 3 ) ^{4}}{16} + \frac{- 16}{16} + \frac{- 3 \cdot 16}{16} = \frac{( 1 + 3 ) ^{4} - 16 - 3 \cdot 16}{16}

= \frac{( 1 + 3 ) ^{4} - 16 - 3 \cdot 16}{16}

Simplify

(1 + 3)^{4} - 16 - 3 \cdot 16 : 12

= \frac{12}{16}

Cancel

\frac{12}{16} : \frac{3}{4}

= \frac{3}{4}

(e^{- x} cos (x) - e^{- x} sin (x))^{2}

\frac{1}{4} (x + 3) - 3

- (x + x \cdot y) d y

\frac{4 + x}{( x - 1 ) ( 4 + x ^{2} )}

\frac{( 2 s + 7 + 6 e ^{- 4 s} )}{( s + 2 ) ( s + 6 )}

What is ((1+sqrt(3))^4)/(16)-1-sqrt(3) ?
The solution to ((1+sqrt(3))^4)/(16)-1-sqrt(3) is 3/4