What is expand ((3+y)^2)/9 ?

The solution to expand ((3+y)^2)/9 is (y^2)/9+(2y)/3+1

Popular >

expand ((3+y)^2)/9

expand

\frac{( 3 + y ) ^{2}}{9}

\frac{y ^{2}}{9} + \frac{2 y}{3} + 1

Solution steps

\frac{( 3 + y ) ^{2}}{9}

(3 + y)^{2} = 9 + 6 y + y^{2}

= \frac{9 + 6 y + y ^{2}}{9}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{9 + 6 y + y ^{2}}{9} = \frac{9}{9} + \frac{6 y}{9} + \frac{y ^{2}}{9}

= \frac{9}{9} + \frac{6 y}{9} + \frac{y ^{2}}{9}

Apply rule

\frac{a}{a} = 1

\frac{9}{9} = 1

= 1 + \frac{6 y}{9} + \frac{y ^{2}}{9}

Cancel

\frac{6 y}{9} : \frac{2 y}{3}

= 1 + \frac{2 y}{3} + \frac{y ^{2}}{9}

Rewrite in standard form

= \frac{y ^{2}}{9} + \frac{2 y}{3} + 1

(\frac{8 x}{5} - \frac{y}{6}) (\frac{8 x}{5} + \frac{y}{6})

\frac{x}{( x ^{2} + 1 ) ^{3}}

\frac{( x - 4 ) ( x + 2 )}{( x - 7 ) ( x - 2 )}

(x + 2 sin (x))^{2}

lo g_{5} (x)

What is expand ((3+y)^2)/9 ?
The solution to expand ((3+y)^2)/9 is (y^2)/9+(2y)/3+1