What is expand 1/((z-2)^2(z-1)) ?

The solution to expand 1/((z-2)^2(z-1)) is 1/(z^3-5z^2+8z-4)

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expand 1/((z-2)^2(z-1))

expand

\frac{1}{( z - 2 ) ^{2} ( z - 1 )}

\frac{1}{z ^{3} - 5 z ^{2} + 8 z - 4}

Solution steps

\frac{1}{( z - 2 ) ^{2} ( z - 1 )}

(z - 2)^{2} = z^{2} - 4 z + 4

= \frac{1}{( z ^{2} - 4 z + 4 ) ( z - 1 )}

Expand

(z^{2} - 4 z + 4) (z - 1) : z^{3} - 5 z^{2} + 8 z - 4

= \frac{1}{z ^{3} - 5 z ^{2} + 8 z - 4}

(2 x^{2} + y) d x + (x^{2} y - x) d y

\frac{1}{2} (x + \frac{1}{2} sin (2 x)) (tan (x))

\frac{x + 6}{x ( x + 13 )}

(x + 7)^{2}

(y) (3 x + 7 y = 62)

What is expand 1/((z-2)^2(z-1)) ?
The solution to expand 1/((z-2)^2(z-1)) is 1/(z^3-5z^2+8z-4)