What is expand (x^2-4x+2)/((x+1)(x-1)) ?

The solution to expand (x^2-4x+2)/((x+1)(x-1)) is (x^2-4x+2)/(x^2-1)

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expand (x^2-4x+2)/((x+1)(x-1))

expand

\frac{x ^{2} - 4 x + 2}{( x + 1 ) ( x - 1 )}

\frac{x ^{2} - 4 x + 2}{x ^{2} - 1}

Solution steps

\frac{x ^{2} - 4 x + 2}{( x + 1 ) ( x - 1 )}

Expand

(x + 1) (x - 1) : x^{2} - 1

= \frac{x ^{2} - 4 x + 2}{x ^{2} - 1}

(x^{\frac{3}{2}} - x + 1) (x^{2} + x^{\frac{1}{2}} - 2)

\frac{5 x ^{3} + 4 x ^{2} + 7 x + 3}{( x ^{2} + 2 x + 2 ) ( x ^{2} - x - 1 )}

\frac{x}{( 1 + x ) ( 1 - 2 x )}

(2 x^{2} + 3 x) (x - 1)

What is expand (x^2-4x+2)/((x+1)(x-1)) ?
The solution to expand (x^2-4x+2)/((x+1)(x-1)) is (x^2-4x+2)/(x^2-1)