What is expand-(2x+2)/((x^2+2x-2)^2) ?

The solution to expand-(2x+2)/((x^2+2x-2)^2) is -(2x+2)/(x^4+4x^3-8x+4)

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expand-(2x+2)/((x^2+2x-2)^2)

expand

- \frac{2 x + 2}{( x ^{2} + 2 x - 2 ) ^{2}}

- \frac{2 x + 2}{x ^{4} + 4 x ^{3} - 8 x + 4}

Solution steps

- \frac{2 x + 2}{( x ^{2} + 2 x - 2 ) ^{2}}

(x^{2} + 2 x - 2)^{2} = x^{4} + 4 x^{3} - 8 x + 4

= - \frac{2 x + 2}{x ^{4} + 4 x ^{3} - 8 x + 4}

\frac{y ( 2 x ^{\frac{1}{4}} - x y ^{\frac{1}{3}} + 1 )}{2 x}

(x - 6)^{4}

10 (y + 5 x) e^{y + 5 x} + e^{y + 5 x} \cdot 5 (y + 5 x)^{2}

\frac{2 x}{( x - 1 ) ( x + 4 ) ( x ^{2} + 1 )}

(x + \frac{1}{2}) (x - \frac{3}{2})

What is expand-(2x+2)/((x^2+2x-2)^2) ?
The solution to expand-(2x+2)/((x^2+2x-2)^2) is -(2x+2)/(x^4+4x^3-8x+4)