What is (7x-1/3)(7x+1/3) ?

The solution to (7x-1/3)(7x+1/3) is ((21x-1)(21x+1))/9

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simplify (7x-1/3)(7x+1/3)

simplify

(7 x - \frac{1}{3}) (7 x + \frac{1}{3})

\frac{( 21 x - 1 ) ( 21 x + 1 )}{9}

Solution steps

(7 x - \frac{1}{3}) (7 x + \frac{1}{3})

Join

7 x - \frac{1}{3} : \frac{21 x - 1}{3}

= \frac{21 x - 1}{3} (7 x + \frac{1}{3})

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 21 x - 1 ) ( 7 x + \frac{1}{3} )}{3}

Simplify

(21 x - 1) (7 x + \frac{1}{3}) : \frac{( 21 x - 1 ) ( 21 x + 1 )}{3}

= \frac{\frac{( 21 x - 1 ) ( 21 x + 1 )}{3}}{3}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( 21 x - 1 ) ( 21 x + 1 )}{3 \cdot 3}

Multiply the numbers:

3 \cdot 3 = 9

= \frac{( 21 x - 1 ) ( 21 x + 1 )}{9}

\frac{e ^{(- 3 s) (4 - 8 s)}}{s ^{2} + 64}

(- 1 + i 3)^{4}

(x + i)^{4}

(8 + 7) (9 + 2)

(x + 5 x^{2})^{2}

What is (7x-1/3)(7x+1/3) ?
The solution to (7x-1/3)(7x+1/3) is ((21x-1)(21x+1))/9