What is expand (2+4sin(θ))^2 ?

The solution to expand (2+4sin(θ))^2 is 4+16sin(θ)+16sin^2(θ)

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expand (2+4sin(θ))^2

expand

(2 + 4 sin (θ))^{2}

4 + 16 sin (θ) + 16 sin^{2} (θ)

Solution steps

(2 + 4 sin (θ))^{2}

Apply Perfect Square Formula:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

(2 + 4 sin (θ))^{2} = 2^{2} + 2 \cdot 2 \cdot 4 sin (θ) + (4 sin (θ))^{2}

= 2^{2} + 2 \cdot 2 \cdot 4 sin (θ) + (4 sin (θ))^{2}

Simplify

2^{2} + 2 \cdot 2 \cdot 4 sin (θ) + (4 sin (θ))^{2} : 4 + 16 sin (θ) + 16 sin^{2} (θ)

= 4 + 16 sin (θ) + 16 sin^{2} (θ)

(x y - x^{2}) (x y + x^{2})

\frac{1}{2} (arcsin (x) - \frac{1}{2} sin (2 arcsin (x)))

(x x - 1) (1 - x)

\frac{z}{( z + 2 ) ( z - 3 )}

(2 - x - 2) (2 + x - 2)

What is expand (2+4sin(θ))^2 ?
The solution to expand (2+4sin(θ))^2 is 4+16sin(θ)+16sin^2(θ)