What is expand (x^2+3x+2)/((3x+1)^2) ?

The solution to expand (x^2+3x+2)/((3x+1)^2) is (x^2+3x+2)/(9x^2+6x+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (x^2+3x+2)/((3x+1)^2)

expand

\frac{x ^{2} + 3 x + 2}{( 3 x + 1 ) ^{2}}

\frac{x ^{2} + 3 x + 2}{9 x ^{2} + 6 x + 1}

Solution steps

\frac{x ^{2} + 3 x + 2}{( 3 x + 1 ) ^{2}}

(3 x + 1)^{2} = 9 x^{2} + 6 x + 1

= \frac{x ^{2} + 3 x + 2}{9 x ^{2} + 6 x + 1}

\frac{1}{( 1 + i 3 ) ^{4}}

\frac{2}{( s ^{2} + 4 ) ( s ^{2} + 1 )}

\frac{- 1}{4} (x + 2)^{2} (x - 1)^{2}

(y + 1) (y + 4 - 4 y + 1)

(e^{x} cos (2 x)) (e^{x} sin (2 x) + 2 e^{x} cos (2 x))

What is expand (x^2+3x+2)/((3x+1)^2) ?
The solution to expand (x^2+3x+2)/((3x+1)^2) is (x^2+3x+2)/(9x^2+6x+1)