What is expand-e^θ(-e^{-θ}θ-e^{-θ}) ?

The solution to expand-e^θ(-e^{-θ}θ-e^{-θ}) is θ+1

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expand-e^θ(-e^{-θ}θ-e^{-θ})

expand

- e^{θ} (- e^{- θ} θ - e^{- θ})

θ + 1

Solution steps

- e^{θ} (- e^{- θ} θ - e^{- θ})

Apply the distributive law:

a (b - c) = ab - a c

a = - e^{θ}, b = - e^{- θ} θ, c = e^{- θ}

= - e^{θ} (- e^{- θ} θ) - (- e^{θ}) e^{- θ}

Apply minus-plus rules

- (- a) = a

= e^{θ} e^{- θ} θ + e^{θ} e^{- θ}

Simplify

e^{θ} e^{- θ} θ + e^{θ} e^{- θ} : θ + 1

= θ + 1

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(4 k - m x) (k b^{2} - \frac{m b ^{2}}{4} x)

\frac{x ^{2} + 1}{( x - 1 ) ^{2}}

(x^{3})^{3}

(a + b + c + d + e + f)^{2}

What is expand-e^θ(-e^{-θ}θ-e^{-θ}) ?
The solution to expand-e^θ(-e^{-θ}θ-e^{-θ}) is θ+1