What is ((-1)^10.5^{2+4})/(1!(2+4)) ?

The solution to ((-1)^10.5^{2+4})/(1!(2+4)) is -0.00260…

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simplify ((-1)^10.5^{2+4})/(1!(2+4))

simplify

\frac{( - 1 ) ^{1} 0. 5 ^{2 + 4}}{1 ! ( 2 + 4 )}

- 0.00260 \dots

Solution steps

\frac{( - 1 ) ^{1} \cdot 0. 5 ^{2 + 4}}{1 ! ( 2 + 4 )}

Apply rule

a^{1} = a

(- 1)^{1} = - 1

= \frac{- 1 \cdot 0. 5 ^{2 + 4}}{1 ! ( 2 + 4 )}

- 1 \cdot 0. 5^{2 + 4} = - 0. 5^{6}

= \frac{- 0. 5 ^{6}}{1 ! ( 2 + 4 )}

Add the numbers:

2 + 4 = 6

= \frac{- 0. 5 ^{6}}{6 \cdot 1 !}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{0. 5 ^{6}}{1 ! \cdot 6}

0. 5^{6} = 0.015625

= - \frac{0.015625}{6 \cdot 1 !}

1! \cdot 6 = 6

= - \frac{0.015625}{6}

Divide the numbers:

\frac{0.015625}{6} = 0.00260 \dots

= - 0.00260 \dots

7 x^{2} - 112

(\frac{a}{b})^{- 10}

\frac{x + 2}{x - 1} \leq 0

6 c^{2} + 2 c^{4} + c

x + 6 = 5 x - 26

What is ((-1)^10.5^{2+4})/(1!(2+4)) ?
The solution to ((-1)^10.5^{2+4})/(1!(2+4)) is -0.00260…