What is 2cos(t)(1/t-t) ?

The solution to 2cos(t)(1/t-t) is (2cos(t)(-t^2+1))/t

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simplify 2cos(t)(1/t-t)

simplify

2 cos (t) (\frac{1}{t} - t)

\frac{2 cos ( t ) ( - t ^{2} + 1 )}{t}

Solution steps

2 cos (t) (\frac{1}{t} - t)

Join

\frac{1}{t} - t : \frac{- t ^{2} + 1}{t}

= 2 cos (t) \frac{- t ^{2} + 1}{t}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 cos ( t ) ( - t ^{2} + 1 )}{t}

(8 x^{\frac{3}{4}} - 2 x^{5})^{2}

\frac{e ^{- s}}{s ( s - 3 ) ( s - 2 )}

\frac{4 - x}{1 + 2 x}

\frac{3 e ^{- s} - 3 s ^{- 2 s}}{s ( s ^{2} - 1 )}

(3 sin (x) + cos (x))^{2}