What is expand ((2-t)^2)/2 ?

The solution to expand ((2-t)^2)/2 is (t^2)/2-2t+2

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expand ((2-t)^2)/2

expand

\frac{( 2 - t ) ^{2}}{2}

\frac{t ^{2}}{2} - 2 t + 2

Solution steps

\frac{( 2 - t ) ^{2}}{2}

(2 - t)^{2} = 4 - 4 t + t^{2}

= \frac{4 - 4 t + t ^{2}}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{4 - 4 t + t ^{2}}{2} = \frac{4}{2} - \frac{4 t}{2} + \frac{t ^{2}}{2}

= \frac{4}{2} - \frac{4 t}{2} + \frac{t ^{2}}{2}

Divide the numbers:

\frac{4}{2} = 2

= 2 - 2 t + \frac{t ^{2}}{2}

Rewrite in standard form

= \frac{t ^{2}}{2} - 2 t + 2

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