What is expand ((x+2)(x-3))/x ?

The solution to expand ((x+2)(x-3))/x is x-1-6/x

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expand ((x+2)(x-3))/x

expand

\frac{( x + 2 ) ( x - 3 )}{x}

x - 1 - \frac{6}{x}

Solution steps

\frac{( x + 2 ) ( x - 3 )}{x}

Expand

(x + 2) (x - 3) : x^{2} - x - 6

= \frac{x ^{2} - x - 6}{x}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{2} - x - 6}{x} = \frac{x ^{2}}{x} - \frac{x}{x} - \frac{6}{x}

= \frac{x ^{2}}{x} - \frac{x}{x} - \frac{6}{x}

Apply rule

\frac{a}{a} = 1

\frac{x}{x} = 1

= \frac{x ^{2}}{x} - 1 - \frac{6}{x}

Cancel

\frac{x ^{2}}{x} : x

= x - 1 - \frac{6}{x}

\frac{x ( 2 x ^{3} + y )}{6 y ^{2}}

\frac{\frac{d}{d x} ( x ^{3} - 2 )}{( 4 x + 3 ) ( 6 x - 2 )}

(a + b) a^{3} - a^{2} b + a b^{2}

\frac{sin ^{2} ( x ) ( 1 + cos ( x ) )}{1 - cos ( x )}

\frac{- S ^{3} - S}{4 ( S ^{4} + S ^{2} + 4 )}

What is expand ((x+2)(x-3))/x ?
The solution to expand ((x+2)(x-3))/x is x-1-6/x