What is expand (x^3+8)/((x^2-1)(x-2)) ?

The solution to expand (x^3+8)/((x^2-1)(x-2)) is (x^3+8)/(x^3-2x^2-x+2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (x^3+8)/((x^2-1)(x-2))

expand

\frac{x ^{3} + 8}{( x ^{2} - 1 ) ( x - 2 )}

\frac{x ^{3} + 8}{x ^{3} - 2 x ^{2} - x + 2}

Solution steps

\frac{x ^{3} + 8}{( x ^{2} - 1 ) ( x - 2 )}

Expand

(x^{2} - 1) (x - 2) : x^{3} - 2 x^{2} - x + 2

= \frac{x ^{3} + 8}{x ^{3} - 2 x ^{2} - x + 2}

\frac{( 2 x + 1 ) ^{3}}{( 2 x - 1 ) ^{2}}

(2 - 2 i 3)^{4}

\frac{1}{( 1 - j ) ^{12}}

(\frac{1}{x} + x) (1 - \frac{1}{x + 1})

2 (11 - 7)

What is expand (x^3+8)/((x^2-1)(x-2)) ?
The solution to expand (x^3+8)/((x^2-1)(x-2)) is (x^3+8)/(x^3-2x^2-x+2)