What is expand (at-1)\H(at-1) ?

The solution to expand (at-1)\H(at-1) is at\H(at-1)-\H(at-1)

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expand (at-1)\H(at-1)

expand

(a t - 1) H (a t - 1)

a t H (a t - 1) - H (a t - 1)

Solution steps

(a t - 1) H (a t - 1)

= H (a t - 1) (a t - 1)

Apply the distributive law:

a (b - c) = ab - a c

a = H (a t - 1), b = a t, c = 1

= H (a t - 1) a t - H (a t - 1) \cdot 1

= a t H (a t - 1) - 1 \cdot H (a t - 1)

Multiply:

1 \cdot H (a t - 1) = H (a t - 1)

= a t H (a t - 1) - H (a t - 1)

(57 x - 3)^{2}

\frac{1}{z ( z - 1 )}

(x^{2} + y^{2}) d x + 2 x y d y

5 (ln (3 x - 4) + \frac{3 x}{3 x - 4})

\frac{1}{2} (x - \frac{π}{4})

What is expand (at-1)\H(at-1) ?
The solution to expand (at-1)\H(at-1) is at\H(at-1)-\H(at-1)